Match list I and list II. List I List II A. 21H+31H→42He+10n+17.6MeV 1. Artificial radioactivity
B. 23592U+10n→14356Ba+9036Kr+310n+200Mev 2. Isodiaphers
C. 2313Al+42He→3014Si+11H 3. Atom Bomb
D. mZA−α→m−4Z−2B 4. Nuclear Fissio 5. Nuclear Fusion
A
A - 5; B - 3,4; C - 1; D - 2
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B
A - 2; B - 3,4; C - 1; D - 5
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C
A - 1,5; B - 3; C - 4; D - 2
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D
A - 3,4; B - 1; C - 5; D - 4,2
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Solution
The correct option is A A - 5; B - 3,4; C - 1; D - 2
Converting a stable atom into a suitable radioactive element is called artificial radioactivity.
Nuclei and its decay product have the same difference of n and p i.e., (n−p)=m−2Z(n−p)=m−2Z, hence isodiaphers.
An atom bomb is weapon with great explosion power that results come from sudden release of energy in fission reactions of heavy nuclei (uranium,plutonium ).
Process of combining two lighter nuclei to give a heavier nucleus is called nuclear fusion.
Process of splitting of nuclei of heavier atoms into two nuclei of comparable masses is called nuclear fission.