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Question

Match list I and list II.
List I List II
A. 21H+31H42He+10n+17.6MeV 1. Artificial radioactivity


B. 23592U+10n14356Ba+9036Kr+310n+200Mev 2. Isodiaphers

C. 2313Al+42He3014Si+11H 3. Atom Bomb

D. mZAαm4Z2B 4. Nuclear Fissio 5. Nuclear Fusion

A
A - 5; B - 3,4; C - 1; D - 2
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B
A - 2; B - 3,4; C - 1; D - 5
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C
A - 1,5; B - 3; C - 4; D - 2
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D
A - 3,4; B - 1; C - 5; D - 4,2
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Solution

The correct option is A A - 5; B - 3,4; C - 1; D - 2
  • Converting a stable atom into a suitable radioactive element is called artificial radioactivity.
  • Nuclei and its decay product have the same difference of n and p i.e., (np)=m2Z(n−p)=m−2Z, hence isodiaphers.
  • An atom bomb is weapon with great explosion power that results come from sudden release of energy in fission reactions of heavy nuclei (uranium,plutonium ).
  • Process of combining two lighter nuclei to give a heavier nucleus is called nuclear fusion.
  • Process of splitting of nuclei of heavier atoms into two nuclei of comparable masses is called nuclear fission.
  • Thus, A - 5 ; B - 3,4 ; C - 1 ; D - 2

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