Match list - I and list - II.
List I List II
A. $O F_{2}$ 1. Oxidation state of $- 1$ for halogen
B. $C l_{2} O$ 2. Oxidation state of $+ 1$ for halogen
C. $C l O_{2}$ 3. Oxidizing agent
D. $C l_{2} O_{6}$ 4. Gives oxygen with $N a O H$

A - 1,3,4; B - 2,3; C - 3; D - 3

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A - 1,3; B - 3; C - 4; D - 2

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A - 4; B - 2,3; C - 1; D - 3

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A - 2; B - 1; C - 2,3; D - 4

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Solution

The correct option is A A - 1,3,4; B - 2,3; C - 3; D - 3
$O F_{2}$ has F in - 1 oxidation state; it is an oxidizer and gives $O_{2}$ on reaction with $N a O H$ .
$C l_{2} O$ has $C I$ in + 1 state, and is an oxidizer.
$C l O_{2}$ is an oxidizer and with $N a O H$ it gives $N a C l O_{2}$ and $N a C l O_{3}$ .
$C l O_{3}$ is an oxidizer and it gives $N a C l O_{3}$ and $N a C l O_{4}$ with $N a O H$ .

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Similar questions

Match List I with List II and select the correct answer using the codes given below the lists

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(A) $N O_{2}$ (1) +5

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Match List I with List II and select the correct answer using the codes given below the lists

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^{'} n^{'}

P V^{n} = const

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