Question

Match list - I and list - II.
List I List II
A. $O{F}_2$ 1. Oxidation state of $-1$ for halogen
B. $C{l}_{2}O$ 2. Oxidation state of $+1$ for halogen
C. $Cl{O}_2$ 3. Oxidizing agent
D. $C{l}_2{O}_6$ 4. Gives oxygen with $NaOH$

• A. A - 1,3,4; B - 2,3; C - 3; D - 3
• B. A - 1,3; B - 3; C - 4; D - 2
• C. A - 4; B - 2,3; C - 1; D - 3
• D. A - 2; B - 1; C - 2,3; D - 4

Answer 1

The correct option is A A - 1,3,4; B - 2,3; C - 3; D - 3

$O{F}_2$ has F in - 1 oxidation state; it is an oxidizer and gives $O_2$on reaction with $NaOH$.
$C{l}_{2}O$ has $CI$ in + 1 state, and is an oxidizer.
$Cl{O}_2$ is an oxidizer and with $NaOH$ it gives $NaCl{O}_2$ and$NaCl{O}_3$.
$Cl{O}_3$ is an oxidizer and it gives $NaCl{O}_3$and$NaCl{O}_4$ with $NaOH$.