Match list I (Complex ions) with list II (number of unpaired electrons) and select the correct answers:
List I
List II
A
[CrF6]4−
1
One
B
[MnF6]4−
2
two
C
[Fe(CN)6]4−
3
zero
D
[Mn(CN)6]4−
4
four
5
five
A
A−4,B−1,C−2,D−5
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B
A−2,B−5,C−3,D−1
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C
A−4,B−5,C−3,D−1
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D
A−2,B−1,C−3,D−5
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Solution
The correct option is BA−4,B−5,C−3,D−1 (A) The complex ion [CrF6]4− contains four unpaired electrons. (B) The complex ion [MnF6]4− contains five unpaired electrons. (C) The complex ion [Fe(CN)6]4− contains zero unpaired electrons. (D) The complex ion [Mn(CN)6]4− contains one unpaired electrons.