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Question

Match list I (Complex ions) with list II (number of unpaired electrons) and select the correct answers:

List IList II
A[CrF6]4−1One
B[MnF6]4−2two
C[Fe(CN)6]4−3zero
D[Mn(CN)6]4−4four
5five

A
A4,B1,C2,D5
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B
A2,B5,C3,D1
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C
A4,B5,C3,D1
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D
A2,B1,C3,D5
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Solution

The correct option is B A4,B5,C3,D1
(A) The complex ion [CrF6]4 contains four unpaired electrons.
(B) The complex ion [MnF6]4 contains five unpaired electrons.
(C) The complex ion [Fe(CN)6]4 contains zero unpaired electrons.
(D) The complex ion [Mn(CN)6]4 contains one unpaired electrons.

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