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Question

# Match List-I (Compounds) with List-II (Oxidation states of Nitrogen) and select answer using the codes given below the lists.List - IList - II(a) NaN3(1) +5(b) N2H2(2) +2(c)NO(3) âˆ’13(d)N2O5(4)âˆ’1

A
a3b4c2d1
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B
a4b3c2d1
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C
a3b4c1d2
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D
a4b3c1d2
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Solution

## The correct option is A a−3b−4c−2d−1a−3The oxidation state of N in NaN3 is −1/3.The oxidation state of Na is +1. So total oxidation state of 3N atoms will be −1.b−4The oxidation state of N in N2H2 is −1.The oxidation state of H is +1. So oxidation state of N atom will be −1.c−2The oxidation state of N in NO is +2.The oxidation state of O is −2. So oxidation state of N atom will be +2.d−1The oxidation state of N in N2O5 is +5.The oxidation state of O is −2. Total oxidation state of 5O atoms will be 5×(−2)=−10. Total oxidation state of 2N atoms will be +10. So oxidation state of N atom will be +5.

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