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Question

Match List-I (Compounds) with List-II (Oxidation states of Nitrogen) and select answer using the codes given below the lists.


List - IList - II
(a) NaN3(1) +5
(b) N2H2(2) +2
(c)NO(3) 13
(d)N2O5(4)1

A
a3b4c2d1
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B
a4b3c2d1
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C
a3b4c1d2
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D
a4b3c1d2
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Solution

The correct option is A a3b4c2d1
a3
The oxidation state of N in NaN3 is 1/3.
The oxidation state of Na is +1. So total oxidation state of 3N atoms will be 1.
b4
The oxidation state of N in N2H2 is 1.
The oxidation state of H is +1. So oxidation state of N atom will be 1.
c2
The oxidation state of N in NO is +2.
The oxidation state of O is 2. So oxidation state of N atom will be +2.
d1
The oxidation state of N in N2O5 is +5.
The oxidation state of O is 2.
Total oxidation state of 5O atoms will be 5×(2)=10.
Total oxidation state of 2N atoms will be +10.
So oxidation state of N atom will be +5.

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