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Valency and Oxidation States

Match list-I ...

Question

Match list-I (compounds) with list-II (oxidation states of nitrogen).

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Solution

The list of compounds and the oxidation state of nitrogen in the compound is given below:
${N a} N_{3} ⟹ 1 (+ 1) + 3 (x) = 0 ⟹ x = - \frac{1}{3}$
$N_{2} H_{2} ⟹ 2 (x) + 2 (+ 1) = 0 ⟹ x = - 1$
$N O ⟹ 1 (x) + 1 (- 2) = 0 ⟹ x = + 2$
$N_{2} O_{5} ⟹ 2 (x) + 5 (- 2) = 0 ⟹ x = + 5$

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Q. Match List-I (Compounds) with List-II (Oxidation states of nitrogen) and select answer using the codes given below the lists.

	List -I		List-II
$(a)$	$N a N_{3}$	$(1)$	$+ 5$
$(b)$	$N_{2} H_{2}$	$(2)$	$+ 2$
$(c)$	$N O$	$(3)$	$- \frac{1}{3}$
$(d)$	$N_{2} O_{5}$	$(4)$	$- 1$

Q. Match the List-I with List-II and select the correct answer from the given Codes.

List-I	List-II
(Compound)	(Oxidation state of nitrogen)
$N_{2} O_{5}$	$- 2$
$N a N_{3}$	$+ 5$
NO	$- 1 / 3$
$N_{2} H_{4}$	$+ 2$

Q. Match the reactions of metals with dilute

H N O_{3} (i n L i s t I)

with the nitrogen compounds obtained by oxidation/reduction

(i n L i s t I I)

Q. Match the compounds given in list I with the oxidation state of their carbon given in list II.

Q. Match the compounds (in List I) with their oxidation number of N (in List II).

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