Question

Match list-I (Cooordination Compounds) with list-II (Type of Isomerism) and select the correct answer using the codes given below :

	List-I		List-II
A.	$Co(N{H}_3{)}_{4}C{l}_2$	1.	Optical isomerism
B.	$Cis-Co(en{)}_{3}C{l}_2$	2.	Ionization Isomerism
C.	$Co\left(en{)}_2\right(NO{)}_{2}ClSCN$	3.	Co-ordination Isomerism
D.	$Co\left(N{H}_3{)}_{6}Cr\right(CN{)}_6$	4.	Geometrical Isomerism

• A. A-4, B-3, C-2, D-1
• B. A-1, B-4, C-3, D-2
• C. A-4, B-1, C-2, D-3
• D. A-4, B-2, C-3, D-1

Answer 1

The correct option is C A-4, B-1, C-2, D-3

$\left[Co\right(N{H}_3{)}_{4}Cl]$ shows geometrical isomerism. It exists in cis and trans form.
$Cis\left[Co\right(en{)}_{3}C{l}_2]$ shows optical isomerism It exists in $d-$ and $l-$ form. The trans isomer is optically active.
$\left[Co\right(en{)}_{2}ClSCN$ exhibits ionization isomerism.
$\left[Co\right(N{H}_3{)}_6\left]\right[Cr\left(CN{)}_6\right]$ exhibits coordination isomerism.