Question

Match List-I with List-II.

List-II	List-II
a. Sucrose	i. b-D-Galactose and b-D-Glucose
b. Lactose	ii. a-D-Glucose and b-D-Fructose
c. Maltose	iii. a-D- Glucose and a-D-Glucose

Choose the correct answer from the options given below:

• A. (a)-(iii), (b)-(ii), (c)-(i)
• B. (a)-(iii), (b)-(i), (c)-(ii)
• C. (a)-(i), (b)-(iii), (c)-(ii)
• D. (a)-(ii), (b)-(i), (c)-(iii)

Answer 1

The correct option is D

(a)-(ii), (b)-(i), (c)-(iii)

The explanation for the correct option:

(D)(a)-(ii), (b)-(i), (c)-(iii)

(a)Sucrose →(ii) a-D- Glucose and b-D- Fructose

α−α− D-glucose and β−β− D-fructose are the two sugars that make up sucrose,The α,β -glycosidic bond holds these two monosaccharide molecules together.

(b)Lactose →(i) b-D- Galactose and b-D- Glucose

Another name for lactose is milk sugar. It is a disaccharide that is formed when glucose and galactose combine to form a linkage known as a β-1→4glycosidic bond. The scientific name for lactose is β-D-galactopyranosyl (1→4)-D-glucose. Since there are two possible forms of glucose in this situation, while only one form of galactose is present, α-lactose and $\beta$-lactose are anomalous forms of the glucopyranose ring.

(c )Maltose → (iii)a-D- Glucose and a-D- Glucose

Two molecules of the monosaccharide glucose combine to form maltose, The bonding between the first glucose carbon atom and the fourth carbon of the second glucose molecule is α-1-4, On hydrolysis by acid or by the maltase enzyme, one mole of maltose yields two moles of D-glucose.

Hence, option (D) is correct.

List (i)	List (ii)
(a)Sucrose	(ii) a-D- Glucose and b-D- Fructose
(b)Lactose	(i) b-D- Galactose and b-D- Glucose
(c )Maltose	(iii)a-D- Glucose and a-D- Glucose