Match list I with list II and elect the correct answer-List I IsotopeList II CharacteristicA- 126Ca1- unstable- -emitterB- 13363I2- unstable- -emitterC- 12153I3- unstable- positron emitterD- 23290Th4- stable

The correct option is D A 4, B 2, C 3, D 1(A) The isotope ^12_6Ca is stable(B) The isotope nbsp; ^133_63I is unstable in nature. It is β em ...

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Byju's Answer

Standard XII

Chemistry

Nucleus Common Terms

Match list I ...

Question

Match list I with list II and elect the correct answer:
List I (Isotope) List II (Characteristic)
A. $_{6}^{12} C a$ 1. unstable, $α$ -emitter
B. $_{63}^{133} I$ 2. unstable, $β$ -emitter
C. $_{53}^{121} I$ 3. unstable, positron emitter
D. $_{90}^{232} T h$ 4. stable

A-1, B-2, C-3, D-4

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A-1, B-3, C-2, D-4

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A-4, B-3, C-2, D-1

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A-4, B-2, C-3, D-1

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Solution

The correct option is D A-4, B-2, C-3, D-1
(A) The isotope $_{6}^{12} C a$ is stable
(B) The isotope $_{63}^{133} I$ is unstable in nature. It is $β$ -emitter.
(C) The isotope $_{53}^{121} I$ is unstable in nature. It is positron emitter.
(D) The isotope $_{90}^{232} T h$ is unstable in nature. It is $α$ -emitter.

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Similar questions

Q. Match List I with List II and select the correct answer.

List I (Isotope)	List II (Characteristic)
A. $_{20}^{40} C a$	$1.$ Unstable, $α - e m i t t e r$
B. $_{53}^{133} I$	$2.$ Unstable, $β - e m i t t e r$
C. $_{53}^{121} I$	$3.$ Unstable, positron emitter
D. $_{90}^{232} T h$	$4.$ Stable

Match the entries in column I with the entries in column II.
$\begin{matrix} Elements & Electronic configuration (i) C^{- 4} is highly unstable because & (a) It would be difficult for carbon with six protons in its nucleus to hold on just two electrons. (ii) C^{+ 4} is achieved by & (b) gaining four electrons to its outermost orbit (iii) C^{+ 4} is highly unstable because & (c) losing four valence electrons (iv) C^{- 4} is achieved by & (d) It is difficult for the nucleus with six protons to hold on ten electrons, i.e. four extra electrons \end{matrix}$

Q. Match the List-I and List-II and select the correct answer using the codes given below the lists:

List-I Isotope	List-II Characteristics
$(A)$ $_{20}^{40} C a$	$(i)$ Unstable, $α$ -emitter
$(B)$ $_{53}^{133} I$	$(i i)$ Unstable, $β$ -emitter
$(C)$ $_{53}^{121} I$	$(i i i)$ Unstable, positron emitter
$(D)$ $_{90}^{232} T h$	$(i v)$ Stable

Q. Consider the four processes

A, B, C, D

shown in the graph given below

List I shows process & List II gives value of index

^{'} n^{'}

for the equation

P V^{n} = const

Match List I with list II.

\begin{matrix} List I & List II A . & A & 1. & 0 B & B & 2 & 1 C & C & 3. & 1.4 D & D & 4. & \infty \end{matrix}

Match List-I with List-II and select the correct answer using the codes given below the lists.

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List I (Isotope)	List II (Characteristic)
A. $_{6}^{12} C a$	1. unstable, $α$ -emitter
B. $_{63}^{133} I$	2. unstable, $β$ -emitter
C. $_{53}^{121} I$	3. unstable, positron emitter
D. $_{90}^{232} T h$	4. stable

Match list I with list II and elect the correct answer:List I (Isotope)List II (Characteristic)A. 126Ca1. unstable, α-emitterB. 13363I2. unstable, β-emitterC. 12153I3. unstable, positron emitterD. 23290Th4. stable

The correct option is D A-4, B-2, C-3, D-1(A) The isotope 126Ca is stable(B) The isotope 13363I is unstable in nature. It is β-emitter.(C) The isotope 12153I is unstable in nature. It is positron emitter.(D) The isotope 23290Th is unstable in nature. It is α-emitter.

Match list I with list II and elect the correct answer:
List I (Isotope) List II (Characteristic)
A. $_{6}^{12} C a$ 1. unstable, $α$ -emitter
B. $_{63}^{133} I$ 2. unstable, $β$ -emitter
C. $_{53}^{121} I$ 3. unstable, positron emitter
D. $_{90}^{232} T h$ 4. stable