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Bond Order and Enthalpy

Match List I ...

Question

Match List I with List II and select the answer from the given codes.

List I List II
A. $C (s) + O_{2} (g) ⟶ C O_{2} (g)$ 1. $Δ H = Δ U + R T$
B. $N_{2} (g) + 3 H_{2} (g) ⟶ 2 N H_{3} (g)$ 2. $Δ H = Δ U$
C. $N H_{4} H S (s) ⟶ N H_{3} (g) + H_{2} S (g)$ 3. $Δ H = Δ U - 2 R T$
D. $P C l_{5} (g) ⟶ P C l_{3} (g) + C l_{2} (g)$ 4. $Δ H = Δ U + 2 R T$
E. $2 S O_{2} (g) + O_{2} (g) ⟶ 2 S O_{3} (g)$ 5. $Δ H = Δ U - R T$

A

A - 1, B - 2, C - 3, D - 4, E - 5

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B

A - 5, B - 2, C - 3, D - 4, E - 1

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C

A - 1, B - 3, C - 4, D - 2, D - 5

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D

A - 2, B - 3, C - 4, D - 1, E - 5

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Solution

The correct option is C $A - 2, B - 3, C - 4, D - 1, E - 5$
As we know,

$Δ H = Δ U + Δ n R T$
$C (s) + O_{2} (g) ⟶ C O_{2} (g)$
$Δ n = 0$ so $Δ H = Δ U$

$N_{2} (g) + 3 H_{2} (g) ⟶ 2 N H_{3} (g)$
$Δ n = 0$ so $Δ H = Δ U - 2 R T$

$N H_{4} H S (s) ⟶ N H_{3} (g) + H_{2} S (g)$
$Δ n = + 2$ so $Δ H = Δ U + 2 R T$

$P C l_{5} (g) ⟶ P C l_{3} (g) + C l_{2} (g)$
$Δ n = 1$ so $Δ H = Δ U + R T$

$2 S O_{2} (g) + O_{2} (g) ⟶ 2 S O_{3} (g)$
$Δ n = - 1$ so $Δ H = Δ U - R T$

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Similar questions

Q. Match List I with List II and select the answer from the given codes
List I List II
A.

C (s) + O_{2} (g) ⟶ C O_{2} (g)

Δ H = Δ U + R T

N_{2} (g) + 3 H_{2} (g) ⟶ 2 N H_{3} (g)

Δ H = Δ U

N H_{4} H S (s) ⟶ N H_{3} (g) + H_{2} S (g)

Δ H = Δ U - 2 R T

P C l_{5} (g) ⟶ P C l_{3} (g) + C l_{2} (g)

Δ H = Δ U + 2 R T

2 S O_{2} (g) + O_{2} (g) ⟶ 2 S O_{3} (g)

Δ H = Δ U - R T

Δ H > Δ U

Δ H < Δ U

.

C (g r a p h i t e) + O_{2} (g) ⟶ C O_{2} (g)

P C l_{5} (g) ⟶ P C l_{3} (g) + C l_{2} (g)

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