Question

Match List - I with List - II and select the correct answer using the codes given below:

List - I (Ion involved)	List - II (agent)
(i) $N{i}^{2+}$	(A) Sodium thiosulphate
(ii) $A{g}^{+}$	(B) Sodium nitroprusside
(iii) $C{u}^{2+}$	(C) Ammonia
(iv) $S^{2-}$	(D) Dimethylglyoxime

• A. $CADB$
• B. $DCAB$
• C. $DCBA$
• D. $DACB$

Answer 1

Answer: (D)

$DACB$

$N{i}^{2+}$ ion forms a complex with DMG (dimethyl glyoxime) to form a complex which has a cherry-red precipitate

$N{i}^{2+}+2DMG\underset{-2H_{2}O}{\overset{+2O{H}^{-}}{\to }}\underset{Cherryredprecipitate}{\left[Ni\right(DMG{)}_2]}$.

$A{g}^{+}$ ion reacts with sodium thiosulfate to form a complex $N{a}_3\left[Ag\right(S_2{O}_3{)}_2]$

$A{g}^{+}+2N{a}_2{S}_2{O}_3\rightleftharpoons N{a}_3\left[Ag\right(S_2{O}_3{)}_2]+N{a}^{+}$

$C{u}^{2+}$ ions react with ammonia to form a deep blue complex

$C{u}^{2+}+4N{H}_3\rightleftharpoons \underset{deepblue}{\left[Cu\right(N{H}_3{)}_4{]}^{2+}}$

$S^{2-}$ reacts with Sodium nitroprusside $\left(N{a}_2\right[Fe\left(CN{)}_{5}NO\right])$ to form a complex $\left[Fe\right(CN{)}_{5}NOS{]}^{4-}$

This results in deep violet coloration and is used as a test for the detection of sulfides.

$S^{2-}+N{a}_2\left[Fe\right(CN{)}_{5}NO]\leftrightharpoons [Fe(CN{)}_{5}NOS{]}^{4-}+2N{a}^{+}$

Thus the correct answer is option D.