Question

Match List I with List II and select the correct answer using the codes given below the lists

List I (Compound) List II (Oxidation state of N)

(A) $N{O}_2$ (1) +5

(B) $HNO$ (2) -3

(C) $N{H}_3$ (3) +4

(D) $N_2{O}_5$ (4) +1

• A. $\stackrel{A}{2}\stackrel{B}{3}\stackrel{C}{4}\stackrel{D}{1}$
• B. $\stackrel{A}{3}\stackrel{B}{1}\stackrel{C}{2}\stackrel{D}{4}$
• C. $\stackrel{A}{3}\stackrel{B}{4}\stackrel{C}{2}\stackrel{D}{1}$
• D. $\stackrel{A}{2}\stackrel{B}{3}\stackrel{C}{1}\stackrel{D}{4}$

Answer 1

The correct option is C

$\stackrel{A}{3}\stackrel{B}{4}\stackrel{C}{2}\stackrel{D}{1}$

Let us calculate the oxidation numbers for Nitrogen in each case:
(a) $\stackrel{\bullet }{N{O}_2};x-(2\times 2)=0;x=+4$
(b) $\stackrel{\bullet }{HNO};1+x-(2\times 1)=0;x=+1$
(c) $\stackrel{\bullet }{N{H}_3};x+(3\times 1)=0;x=-3$
(d) $\stackrel{\bullet }{N_2{O}_5};2x-(5\times 2)=0;$

$x=\frac{10}{2};x=5$