Question

Match List -I with List - II.
$\begin{array}{cccc}& \text{List-I}& & \text{List-II}\\ & \text{(Products formed)}& & \text{(Reaction of carbonyl}\\ & & & \text{compound with)}\\ \text{(a)}& \text{Cyanohydrin}& \text{(i)}& N{H}_{2}OH\\ \text{(b)}& \text{Acetal}& \text{(ii)}& RN{H}_2\\ \text{(c)}& \text{Schiff's base}& \text{(iii)}& \text{alcohol}\\ \text{(d)}& \text{Oxime}& \text{(iv)}& HCN\end{array}$
Choose the correct answer from the options given below.

Answer 1

Aldehydes undergo nucleophilic addition with alcohols form hemi-acetals & acetals.
Nucleophilic addition of $HCN$ to the carbonyl compounds results in the formation of cyanohydrins.
Nucleophilic addition of primary amines to aldehydes/ketones result in the formation of imines or schiff's base.

Nucleophilic addition of hydroxylamine to aldehydes/ketones leads to the formation of oximes.

Cyanohydrin $\to HCN$
Acetal $\to$ Alcohol
Schiff's base $\to R–N{H}_2$
Oxime $\to N{H}_2–OH$