Question

Match List - I with List - II for the compositions of substances and select the correct answer using the code given below the list:
List - I List - II
Substances Composition
(A) Plaster of paris (i) $CaS{O}_4\cdot 2H_{2}O$
(B) Epsomite (ii) $Cas{O}_4\cdot \frac{1}{2}{H}_{2}O$
(C) Kieserite (iii) $MaS{O}_4\cdot 7H_{2}O$
(D) Gypsum (iv) $MgS{O}_4\cdot H_{2}O$
(v) $CaS{O}_4$

• A. (A) - (iii), (B) - (iv), (C) - (i), (D) - (ii)
• B. (A) - (ii), (B) - (iii), (C) - (iv), (D) - (i)
• C. (A) - (i), (B) - (ii), (C) - (iii), (D) - (v)
• D. (A) - (iv), (B) - (iii), (C) - (ii), (D) - (i)

Answer 1

The correct option is B (A) - (ii), (B) - (iii), (C) - (iv), (D) - (i)

(A) Plaster of paris is calcium sulphate hemihydrate $CaS{O}_4\cdot \frac{1}{2}{H}_{2}O$. It is a white powder.
(B) Epsomite is magnesium sulphate heptahydrate $MgS{O}_4\cdot 7H_{2}O$. It is also written as $\left[Mg\right(H_{2}O{)}_6]S{O}_4.H_{2}O$. It is also called epsom salt.
(C) Kieserite is magnesium sulphate monohydrate $MgS{O}_4\cdot H_{2}O$
(D) Gypsum is calcium sulphate dihydrate $=CaS{O}_4\cdot 2H_{2}O$. It exists in monoclinic and orthorhombic form.