Question

Match List - I with List - II

Choose the correct answer from the options given below:
List - I List - II (a) \( Cu _{2} Cl _{2} \) (i) Wurtz reaction (b) \( Cu / HCl \) (ii) Sandmeyer reaction (c) \( 2 CH _{3} CH _{2} Cl +2 Na \) (iii) Fittig reaction \( \stackrel{\text { Ether }}{\rightarrow} C _{2} H _{5}- C _{2} H _{5}+2 NaCl \) (d) \( 2 C _{6} H _{5} Cl +2 Na \) (iv) Gatterman \( \stackrel{\text { Ether }}{\longrightarrow} C _{6} H _{5}- C _{6} H _{5}+2 NaCl \) reaction

• A. (a) - (iii); (b) - (i); (c) - (iv); (d) - (ii)
• B. (a) - (ii); (b) - (i); (c) - (iv); (d) - (iii)
• C. (a) - (ii); (b) - (iv); (c) - (i); (d) - (iii)
• D. (a) - (iii); (b) - (iv); (c) - (i); (d) - (ii)

Answer 1

The correct option is C (a) - (ii); (b) - (iv); (c) - (i); (d) - (iii)

Fittig reaction in which 2 molecules of aryl halide reacts with 2 mole of Na in presence of ether to form biphenyl.
The reaction is as follows:
Hence, (d) - Fittig reaction.

Wurtz reaction in which 2 molecules of alkyl halide reacts with 2 mole of Na in presence of ether to form higher hydrocarbons.
Hence, (c) - Wurtz reaction.

Reaction of benzene diazonium salt with $Cu{X}_2$ to form Aryl halide is called Sandmeyer reaction.
$C_6{H}_5{N}_2^{+}{X}^{-}\stackrel{C{u}_2{X}_2}{\to }{C}_6{H}_{5}X$
Hence, (a) - Sandmeyer reaction.

Gattermann reaction is used for obtaining chlorobenzene or bromobenzene from benzenediazonium chloride by treating it with Cu/HCl or Cu/HBr respectively.
Hence, (b) - Gatterman reaction.

Therefore, option (b) is correct.