Question

Match List - I with List - II.

List - I	List - II
$a.h$ $($Planck's Constant$)$	$i.\left[ML{T}^{-1}\right]$
$b.E$ $($Kinetic Energy$)$	$ii.\left[M{L}^2{T}^{-1}\right]$
$c.V$ $($Electric Potential$)$	$iii.\left[M{L}^2{T}^{-2}\right]$
$d.P$ $($Linear Momentum$)$	$iv.\left[M{L}^2{I}^{-1}{T}^{-3}\right]$

Choose the correct answer from the options given below.

• A. $\left(a\right)\to \left(ii\right),\left(b\right)\to \left(iii\right),\left(c\right)\to \left(iv\right),\left(d\right)\to \left(i\right)$
• B. $\left(a\right)\to \left(i\right),\left(b\right)\to \left(ii\right),\left(c\right)\to \left(iv\right),\left(d\right)\to \left(iii\right)$
• C. $\left(a\right)\to \left(iii\right),\left(b\right)\to \left(ii\right),\left(c\right)\to \left(iv\right),\left(d\right)\to \left(i\right)$
• D. $\left(a\right)\to \left(iii\right),\left(b\right)\to \left(iv\right),\left(c\right)\to \left(ii\right),\left(d\right)\to \left(i\right)$

Answer 1

The correct option is A $\left(a\right)\to \left(ii\right),\left(b\right)\to \left(iii\right),\left(c\right)\to \left(iv\right),\left(d\right)\to \left(i\right)$

$\left(i\right).$ Planck Constant, $h=\frac{E}{f}$
$\Rightarrow \left[h\right]=\left[\frac{E}{f}\right]=\left[M{L}^2{T}^{-1}\right]$

$\left(ii\right).$ Kinetic Energy, $E=\frac{1}{2}m{v}^2$
$\Rightarrow \left[E\right]=\left[\frac{1}{2}m{v}^2\right]=\left[M{L}^2{T}^{-2}\right]$

$\left(iii\right).$ Electric Potential, $V=\frac{W}{q}=\frac{W}{It}$
$\Rightarrow \left[V\right]=\left[\frac{W}{It}\right]=\left[M{L}^2{I}^{-1}{T}^{-3}\right]$

$\left(iv\right).$ Linear Momentum, $P=mv$
$\Rightarrow \left[P\right]=\left[mv\right]=\left[ML{T}^{-1}\right]$