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Question

# Match List-I with List-II : List–I List–II (a) ωL>1ωC (i) Current is in same phase with emf. (b) ωL=1ωC (ii) Current lags behind the applied emf. (c) ωL<1ωC (iii) Maximum current occurs. (d) Resonant frequency (iv) Current leads the emf. Choose the correct answer from the options given below :

A
(a)(ii);(b)(i);(c)(iv);(d)(iii)
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B
(a)(iii);(b)(i);(c)(iv);(d)(ii)
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C
(a)(ii);(b)(i);(c)(iii);(d)(iv)
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D
(a)(iv);(b)(iii);(c)(ii);(d)(i)
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Solution

## The correct option is A (a)–(ii);(b)–(i);(c)−(iv);(d)–(iii)We know that, XL=ωL and XC=1ωC Option (a): For XL>XC,, the circuit is inductive, so voltage leads the current. So, (a)−(ii). Option (b): For XL=XC,, resonance condition, voltage & current are in same phase. So, (b)−(i). Option (c): For XL<XC,, the circuit is capacitive, so current leads the voltage. So, (c)−(iv). Option (d): For resonant frequency, current is maximum. So, (d)−(iii). Hence, (A) is the correct answer.

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