CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Match List-I with List-II :

List–I List–II
(a) ωL>1ωC (i) Current is in same phase with emf.
(b) ωL=1ωC (ii) Current lags behind the applied emf.
(c) ωL<1ωC (iii) Maximum current occurs.
(d) Resonant frequency (iv) Current leads the emf.

Choose the correct answer from the options given below :

A
(a)(ii);(b)(i);(c)(iv);(d)(iii)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
(a)(iii);(b)(i);(c)(iv);(d)(ii)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
(a)(ii);(b)(i);(c)(iii);(d)(iv)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
(a)(iv);(b)(iii);(c)(ii);(d)(i)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A (a)(ii);(b)(i);(c)(iv);(d)(iii)
We know that,

XL=ωL and XC=1ωC

Option (a): For XL>XC,, the circuit is inductive, so voltage leads the current.
So, (a)(ii).

Option (b): For XL=XC,, resonance condition, voltage & current are in same phase.
So, (b)(i).

Option (c): For XL<XC,, the circuit is capacitive, so current leads the voltage.
So, (c)(iv).

Option (d): For resonant frequency, current is maximum.
So, (d)(iii).

Hence, (A) is the correct answer.

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon