Match List - I with List -IIList-I List-II a- Sucrosei- -D-Galactose and -D-Glucoseb- Lactoseii- -D-Glucose and -D-Fructosec- Maltoseiii- -D- Glucose and -D-GlucoseChoose the correct answer from the options given below-

Disaccharides hydrolysed to give 2 unit of monosaccharides. nbsp; Lactose : Sucrose: Maltose: MaltoseC_12H_22O_11α D glucoseC_6H_12O_6+ α D glucoseC_6H_12O_6 ...

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Byju's Answer

Standard XII

Chemistry

Glucose

Match List - ...

Question

Match List - I with List -II

List-I List-II

a. Sucrose i. $β$ -D-Galactose and $β$ -D-Glucose

b. Lactose ii. $α$ -D-Glucose and $β$ -D-Fructose

c. Maltose iii. $α$ -D- Glucose and $α$ -D-Glucose

Choose the correct answer from the options given below:

(a)-(iii), (b)-(ii), (c)-(i)

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(a)-(iii), (b)-(i), (c)-(ii)

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(a)-(i), (b)-(iii), (c)-(ii)

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(a)-(ii), (b)-(i), (c)-(iii)

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Solution

The correct option is D (a)-(ii), (b)-(i), (c)-(iii)
Disaccharides hydrolysed to give 2 unit of monosaccharides.
Lactose :
Sucrose:

Maltose:
$C_{12} H_{22} O_{11} Maltose Hydrolysis - ----- \to C_{6} H_{12} O_{6} α -D-glucose + C_{6} H_{12} O_{6} α -D-glucose$

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Similar questions

Q. Match the following.

List-I	List-II (Monomer)
A) Sucrose	i) $β$ -D-Galactose and $β$ -D-Glucose
B) Cellulose	ii) $α$ -D-Glucose and $β$ -D-Fructose
C) Starch	iii) $β$ -D-Glucose
D) Lactose	iv) $α$ -D-Glucose

Match the List-I and List-II:

List I (Saccharides)	List II (Formed by)
(A) Sucrose	(i) $β$ -D glucose $C_{1} - C_{4}$ glycosidic linkage
(B) Lactose	(ii) $α$ -D glucose, $β$ -D fructose $C_{1} - C_{2}$ glycosidic linkage
(C) Cellulose	(iii) $β$ -D glucose, $β$ -D galactose $C_{1} - C_{4}$ glycosidic linkage

Q. Match the following. (in order A, B, C, D)

List - I	List - II
A) $α$ -D-Glucose and $β$ -D-Glucose	1) Muta-rotation
B) $(+)$ and $(-)$ - Glucose	2) Enantiomers
C) $D$ and $L$ - Glucose	3) Anomers
D) Interconversion of $α$ and $β$ forms of glucose	4) Configurational

The enantiomer of $α - D - (+) -$ glucose is ?

Q. The enthalpy changes of some process are given below :

α - D - g l u c o s e_{(s)} + H_{2} O ⟶ α - D - g l u c o s e_{(a q)}; Δ H_{d i s s o l u t i o n} = 10.84 k J

β - D - g l u c o s e_{(s)} + H_{2} O ⟶ β - D - g l u c o s e_{(a q)}; Δ H_{d i s s o l u t i o n} = 4.68 k J

α - D - g l u c o s e_{(a q)} ⟶ β - D - g l u c o s e_{(a q)}; Δ H_{m u t a r o t a t i o n} = - 1.16 k J

The

Δ H^{\circ}

for

α - D - g l u c o s e ⟶ β - D - g l u c o s e

is :

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List-I	List-II
a. Sucrose	i. $β$ -D-Galactose and $β$ -D-Glucose
b. Lactose	ii. $α$ -D-Glucose and $β$ -D-Fructose
c. Maltose	iii. $α$ -D- Glucose and $α$ -D-Glucose

Match List - I with List -II List-I List-II a. Sucrose i. β-D-Galactose and β-D-Glucose b. Lactose ii. α-D-Glucose and β-D-Fructose c. Maltose iii. α-D- Glucose and α-D-Glucose Choose the correct answer from the options given below:

The correct option is D (a)-(ii), (b)-(i), (c)-(iii)Disaccharides hydrolysed to give 2 unit of monosaccharides. Lactose : Sucrose: Maltose: C12H22O11MaltoseHydrolysis−−−−−−→C6H12O6α-D-glucose+C6H12O6α-D-glucose

Match List - I with List -II

List-I List-II

a. Sucrose i. $β$ -D-Galactose and $β$ -D-Glucose

b. Lactose ii. $α$ -D-Glucose and $β$ -D-Fructose

c. Maltose iii. $α$ -D- Glucose and $α$ -D-Glucose

Choose the correct answer from the options given below:

The correct option is D (a)-(ii), (b)-(i), (c)-(iii)
Disaccharides hydrolysed to give 2 unit of monosaccharides.
Lactose :
Sucrose:

Maltose:
$C_{12} H_{22} O_{11} Maltose Hydrolysis - ----- \to C_{6} H_{12} O_{6} α -D-glucose + C_{6} H_{12} O_{6} α -D-glucose$