Question

Match List-I with List-II.

	List-I		List-II
	Electonic configuration of elements		${\Delta }_{1}H\text{(}inkJmo{l}^{-1})$
(a)	$1s^{2}2s^2$	(i)	$801$
(b)	$1s^{2}2s^{2}2p^4$	(ii)	$899$
(c)	$1s^{2}2s^{2}2p^3$	(iii)	$1314$
(d)	$1s^{2}2s^{2}2p^1$	(iv)	$1402$

Choose the most appropriate answer from the options given below:

• A. $\left(a\right)\to \left(i\right),\left(b\right)\to \left(iii\right),\left(c\right)\to \left(iv\right),\left(d\right)\to \left(ii\right)$
• B. $\left(a\right)\to \left(i\right),\left(b\right)\to \left(iv\right),\left(c\right)\to \left(iii\right),\left(d\right)\to \left(ii\right)$
• C. $\left(a\right)\to \left(iv\right),\left(b\right)\to \left(i\right),\left(c\right)\to \left(ii\right),\left(d\right)\to \left(iii\right)$
• D. $\left(a\right)\to \left(ii\right),\left(b\right)\to \left(iii\right),\left(c\right)\to \left(iv\right),\left(d\right)\to \left(i\right)$

Answer 1

The correct option is D $\left(a\right)\to \left(ii\right),\left(b\right)\to \left(iii\right),\left(c\right)\to \left(iv\right),\left(d\right)\to \left(i\right)$

On moving left to right in periodic table, ionisation energy increases (generally) but group-$13$ elements have lesser $I.E.$ than group-$2$ elements due to stable $n{s}^2$ electronic configuration of group-$2$ elements and group-$15$ elements have greater $I.E.$ than group-$16$ elements due to half-filled stable $n{p}^3$ electronic configuration of group-$15$ elements.
$\therefore$ Overall order of $I.E$ should be
$c>b>a>d$
Hence, D is the correct option.