SF4- S is surrounded by 4 sigma bond pair and 1 lone pair. Thus, its steric number is 5. So it is sp3d hybridised.
IF5- I is surrounded by 5 sigma bond pair and 1 lone pair. Thus, its steric number is 6. So, it is sp3d2 hybridised.
NO+2- N has 2 sigma bond pair and no lone pair. Thus, its steric number is 2. So, it is sp hybridised.
NH+4- N has 4 sigma bond pair and no lone pair. Thus, its steric number is 4. So it is sp3 hybridised.
Hence, option (d) is correct.