Match list-I with list-II:

List-I
(Molecule) List-II
(Bond order)

(a) $N e_{2}$ (i) 1

(b) $N_{2}$ (ii) 2

(c) $F_{2}$ (iii) 0

(d) $O_{2}$ (iv) 3

Choose the correct answer from the options given below

(a) - (i v); (b) - (i i i); (c) - (i i); (d) - (i)

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(a) - (i i); (b) - (i); (c) - (i v); (d) - (i i i)

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(a) - (i); (b) - (i i); (c) - (i i i); (d) - (i v)

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(a) - (i i i); (b) - (i v); (c) - (i); (d) - (i i)

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Solution

The correct option is D $(a) - (i i i); (b) - (i v); (c) - (i); (d) - (i i)$

List-I
(Molecule) List-II
(Bond order)

(a) $N e_{2}$ (iii) 0

(b) $N_{2}$ (iv) 3

(c) $F_{2}$ (i) 1

(d) $O_{2}$ (ii) 2

Hence, the correct option is (d).
$(a) - (i i i); (b) - (i v); (c) - (i); (d) - (i i)$

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	List-I		List-II
	Electonic configuration of elements		$Δ_{1} H (i n k J m o l^{- 1})$
(a)	$1 s^{2} 2 s^{2}$	(i)	$801$
(b)	$1 s^{2} 2 s^{2} 2 p^{4}$	(ii)	$899$
(c)	$1 s^{2} 2 s^{2} 2 p^{3}$	(iii)	$1314$
(d)	$1 s^{2} 2 s^{2} 2 p^{1}$	(iv)	$1402$

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