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Octet Rule

Match list-I ...

Question

Match list-I with list-II:

List-I
(Molecule) List-II
(Bond order)

(a) $N e_{2}$ (i) 1

(b) $N_{2}$ (ii) 2

(c) $F_{2}$ (iii) 0

(d) $O_{2}$ (iv) 3

Choose the correct answer from the options given below
(JEE (MAIN)-2021)

(a) - (i v); (b) - (i i i); (c) - (i i); (d) - (i)

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(a) - (i); (b) - (i i); (c) - (i i i); (d) - (i v)

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(a) - (i i i); (b) - (i v); (c) - (i); (d) - (i i)

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(a) - (i i); (b) - (i); (c) - (i v); (d) - (i i i)

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Solution

The correct option is C $(a) - (i i i); (b) - (i v); (c) - (i); (d) - (i i)$

List-I
(Molecule) List-II
(Bond order)

(a) $N e_{2}$ (iii) 0

(b) $N_{2}$ (iv) 3

(c) $F_{2}$ (i) 1

(d) $O_{2}$ (ii) 2

Hence, the correct option is (d).
$(a) - (i i i); (b) - (i v); (c) - (i); (d) - (i i)$

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