Byju's Answer
Standard XII
Chemistry
Abundance of Elements
Match List-I ...
Question
Match List-I with List-II.
List-I
(Ore)
List-II
(Element present)
(a) Kernite
(i) Tin
(b) Cassiterite
(ii) Boron
(c) Calamine
(iii) Fluorine
(d) Cryolite
(iv) Zinc
A
(a) – (ii), (b) – (iv), (c) – (i), (d) – (iii)
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B
(a) – (ii), (b) – (i), (c) – (iv), (d) – (iii)
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C
(a) – (i), (b) – (iii), (c) – (iv), (d) – (ii)
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D
(a) – (iii), (b) – (i), (c) – (ii), (d) – (iv)
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Solution
The correct option is
B
(a) – (ii), (b) – (i), (c) – (iv), (d) – (iii)
Kernite
(
N
a
2
B
4
O
7
.4
H
2
O
)
Cassiterite
(
S
n
O
2
)
Calamine
(
Z
n
C
O
3
)
Cryolite
(
N
a
3
A
l
F
6
)
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1
Similar questions
Q.
List-I (Metal)
List- II (Ores)
(a) Aluminum
(i) siderite
(b) Iron
(ii) siderite
(c) Copper
(iii) Kaolinite
(d) Zinc
(iv) Malachite
Q.
Match List I to List II :
(A)A-i; B-ii; C-iii; D-iv
(B) A-iv; B-ii; CUi;D-i
(C)
A-iii; B-ii; C-i; D-iv
(D) A-iii; B-i, C-ii, D-iv
Q.
Match List I to List II:
(A)A-i; B-ii; C-iii; D-iv
(B) A-iii; B-i; C-iv; D-ii
(C) A-iv; B-iii; C-ii; D-i
(D) A-(i); B-iii; C-iv; D-ii
Q.
Correctly match list I with list II
L
i
s
t
−
1
L
i
s
t
−
I
I
A
C
o
l
l
a
r
b
o
n
e
i
P
e
c
t
o
r
a
l
g
i
r
d
l
e
B
G
l
e
n
o
i
d
c
a
v
i
t
y
i
i
P
e
l
v
i
c
g
i
r
d
l
e
C
A
c
e
t
a
b
u
l
u
m
i
i
i
P
a
t
e
l
l
a
D
K
n
e
e
c
a
p
i
v
C
l
a
v
i
c
l
e
Q.
List - I
List - II (At STP)
(A)
10
g
C
a
C
O
3
Δ
−
−−−−−−−
→
d
e
c
o
m
p
o
s
i
t
i
o
n
(i)
0.224
L
C
O
2
(B)
1.06
g
N
a
2
C
O
3
E
x
c
e
s
s
H
C
L
−
−−−−−−−
→
(ii)
4.48
L
C
O
2
(C)
2.4
g
C
E
x
c
e
s
s
O
2
−
−−−−−−
→
c
o
m
b
u
s
t
i
o
n
(iii)
0.448
L
C
O
2
(D)
0.56
g
C
O
E
x
c
e
s
s
O
2
−
−−−−−−
→
c
o
m
b
u
s
t
i
o
n
(iv)
2.24
L
C
O
2
(v)
22.4
L
C
O
2
Match the List I with the List II.
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