Question

Match List- I with List -II.

$\text{List I}\text{(Colloid Preparation Method)}$	$\text{List II}\text{Chemical Reaction}$
(a) Hydrolysis	$\left(i\right)2AuC{l}_3+3HCHO+2H_{2}O\to 2Au\left(sol\right)+3HCOOH+6HCl$
(b) Reduction	$\left(ii\right)A{s}_2{O}_3+3H_{2}S\to A{s}_2{S}_3\left(sol\right)+3H_{2}O$
(c) Oxidation	$\left(iii\right)S{O}_2+2H_{2}S\to 3S\left(sol\right)+2H_{2}O$
(d) Double decomposition	$\left(iv\right)FeC{l}_3+3H_{2}O\to Fe\left(OH{)}_3\right(sol)+3HCl$

Choose the most appropriate answer from the options given below

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Answer 1

In reaction $\left(i\right),Au\left(sol\right)$ is formed by reduction of $AuC{l}_3$, so the chemical method of preparation is "Reduction".
In reaction $\left(ii\right).A{s}_2{S}_3\left(sol\right)$ is formed by double decomposition, so the chemical method of preparation is "Double decomposition".
In reaction $\left(iii\right).S\left(sol\right)$ is formed by oxidation of $H_{2}S$, so the chemical method of preparation is "Oxidation".
In reaction $\left(iv\right).Fe\left(OH{)}_3\right(sol)$ is formed by hydrolysis of $FeC{l}_3$ so the chemical method of preparation is "Hydrolysis".
Option (d) is correct