Match manufacturing process $(i n C o l u m n I)$ with catalyst used $(i n C o l u m n I I)$ .

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Solution

(A) $B i^{3 +} + H_{2} O ⟶ (B i O)^{+} + 2 H^{+}$
$B i C l_{3} + H_{2} O \to B i O C l + H C l$
The reaction takes place in presence of water and therefore, it is a hydrolysis or dilution reaction.
(B) $[A l O_{2}]^{-} + H^{+} ⟶ A l (O H)_{3}$
$C a (A l O_{2})_{2} + H C l \to A l C l_{3} + C a C l_{2} + H_{2} O$
The reaction is acidification reaction.
(C) $S i O_{4}^{4 -} ⟶ S i_{2} O_{7}^{6 -}$
$C a_{2} S i O_{4} + 4 H_{2} O \to C a_{3} S i O_{7} .3 H_{2} O + C a (O H)_{2}$
The reaction is a dilution reaction.
(D) $(B_{4} O_{7}^{2 -}) ⟶ [B (O H)_{3}]$
$N a_{2} B_{4} O_{7} + 2 H C l \to 2 N a C l + H_{2} B_{4} O_{7}$
$H_{2} B_{4} O_{7} + H_{2} O \to B (O H)_{3}$
The first reaction is an acidification reaction while the second is dilution with water.

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