Question

Match $\%$ of carbon in List-I with the compound given in List-II.

Answer 1

20% $=C{N}_{2}O{H}_4=12\times 100/60$
75 % $=C{H}_4=12\times 100/16$
12 % $=CaC{O}_3=12\times 100/100$
27.3% $=C{O}_2=12\times 100/44$
52.2% $=C_2{H}_{6}O$