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Question
Match reactions written in List 1 with their mechanism in List 2
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Solution
(i) Ph−CH2−CH2−Br→Ph−CH|OH=CH2+Ph−CH=CH2 has a stable carbo cation due to benzene group attached to it So, Ph−CH2−CH2−Br→Ph−CH|OH=CH2+Ph−CH=CH2 undergoes. SN1 mechanism to give (ii) Ph−CH2−CH2−BrEt(−)O⟶ΔPh−CH2−CH2−OET⇒ As the bromine near i carbon is attacked by Nucleophile. So, Δt is SN2 Mechanism.(iii) ph−CH2−CH2−BrEt(−)o/Etod⟶Δph−CH=CH2The reaction is an unimolecular elimination reaction i.e E1 Mechanism.(iv) ph−CH2−CH2−BrEt(−)o/EtoD⟶ph−CH=CH2+ph−CD2−CH2BrThe reaction is a bimolecular elimination reaction i.e E2 Mechanism.A−1, B−2, C−3, D−4.
(i) Ph−CH2−CH2−Br→Ph−CH|OH=CH2+Ph−CH=CH2 has a stable carbo cation due to benzene group attached to it So, Ph−CH2−CH2−Br→Ph−CH|OH=CH2+Ph−CH=CH2 undergoes. SN1 mechanism to give
(ii) Ph−CH2−CH2−BrEt(−)O⟶ΔPh−CH2−CH2−OET⇒ As the bromine near i carbon is attacked by Nucleophile. So, Δt is SN2 Mechanism.
(iii) ph−CH2−CH2−BrEt(−)o/Etod⟶Δph−CH=CH2
The reaction is an unimolecular elimination reaction i.e E1 Mechanism.
(iv) ph−CH2−CH2−BrEt(−)o/EtoD⟶ph−CH=CH2+ph−CD2−CH2Br
The reaction is a bimolecular elimination reaction i.e E2 Mechanism.
A−1, B−2, C−3, D−4.
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