Question

Match species given in Column I with the electronic configuration given in Column II.

	Column I		Column II
A	$Cr$	(i)	$\left[Ar\right]3d^{8}4s^0$
B	$F{e}^{2+}$	(ii)	$\left[Ar\right]3d^{10}4s^1$
C	$N{i}^{2+}$	(iii)	$\left[Ar\right]3d^{6}4s^0$
D	$Cu$	(iv)	$\left[Ar\right]3d^{5}4s^1$
		(v)	$\left[Ar\right]3d^{6}4s^2$

Answer 1

Analyzing and understanding all the metal atom/ion electronic configurations

A) $Cr(Z=24)=\left[Ar\right]3d^{54}{s}^1$
Due to half filled $d-$orbital

B) $Fe(Z=26)=\left[Ar\right]3d^{64}{s}^2$
$F{e}^2+=\left[Ar\right]3d^{64}{s}^0$

C)$Ni(z=28)=\left[Ar\right]3d^{3}4s^2$
$N{i}^{2+}=\left[Ar\right]3d^{s}4s^0$

D)$Cu(z=29)=\left[Ar\right]3d^{10}4s^1$
Due to fully filled $d-$orbital

Hence, the correct answer is :

	Column I		Column II
A	$Cr$	(iv)	$\left[Ar\right]3d^{5}4s^1$
B	$F{e}^{2+}$	(iii)	$\left[Ar\right]3d^{6}4s^0$
C	$N{i}^{2+}$	(i)	$\left[Ar\right]3d^{8}4s^0$
D	$Cu$	(ii)	$\left[Ar\right]3d^{10}4s^1$