wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Match statements in column I with results in column II for the figure shown.(g=10 m/s2)

Column IColumn II(a)Acceleration of 2 kg block(p)8 SI unit(b)Net force on 3 kg block(q)25 SI unit(c)Normal reaction between(r)2 SI unit2 kg and 1 kg(d)Normal reaction between(s)45 SI unit3 kg and 2 kg(t)None

A
a - s, b - r, c - q, d - p
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
a - r, b - t, c - q, d - t
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
a - s, b - p, c - q, d - r
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
a - r, b - q, c - r, d - p
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B a - r, b - t, c - q, d - t
(a) → (r); (b) → (t); (c) → (q); (d) → (t)



Let a be acceleration of masses together as a system along the inclined plane
42mgsin30=ma
6×10×12+42=6a
12=6a
a=2 m/s2

Net force on 3 kg mass is 3a=6 N

From FBD of 1 kg mass
R18gsin30=a
R185=a
R23=2
R=25 N

From FBD of 3 kg mass
60R3gsin30=3a
60R15=6
45R=6
R=39 N

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Second Law of Motion
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon