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Question

Match List I with the List II and select the correct answer using the code given below the lists :
A pair of dice is rolled and the sum of the numbers that comes up is noted down, then consider the following events
A= sum of numbers is odd
B= sum of numbers is even
C= sum of numbers is more than 11
D= sum of numbers is less than 4
E= sum of numbers is prime number

List-I List-II(a)A and B(p)Simple event(b)C and D(q)Exhaustive events(c)B C(r)Exclusive events(d)A and E(s)Equally likely event

Which of the following is correct combination?

A
(a)(q),(b)(r),(c)(p),(d)(s)
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B
(a)(r),(b)(q),(c)(p),(d)(s)
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C
(a)(p),(b)(q),(c)(s),(d)(r)
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D
(a)(s),(b)(q),(c)(r),(d)(p)
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Solution

The correct option is A (a)(q),(b)(r),(c)(p),(d)(s)
The sample space S={2,3,4,5,6,7,8,9,10,11,12}
A= Sum of nos. is odd
={3,5,7,9,11}
B= Sum of nos. is even
={2,4,6,8,10,12}
C= Sum of nos. is more than 11
={12}
D= Sum of nos is less than 4
={2,3}
E= Sum of nos. is prime no.
={2,3,5,7,11}

AB will contain all the elements AB={2,3,4,5,6,7,8,9,10,11,12}
So, A and B is exhaustive events.

C and D does not have any common element, so they are exclusive events.

BC={12} has only one element, so it is a simple event.

A and E= both have equal no. of elements, so they are equally likely events.

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