Match the anionic species given in Column I that are present in the ore(s) given in Column II. Column IColumn II(A) Carbonate(P) Siderite(B) Sulphide(Q) Malachite(C) Hydroxide(R) Bauxite(D) Oxide(S) Calamine(T) Argentite
A
A→P,Q,S;B→T;C→Q,R;D→R
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B
A→P,S;B→Q;C→Q,T;D→P
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C
A→Q,S;B→S;C→Q;D→P
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D
A→P,Q;B→R;C→Q,R;D→T
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Solution
The correct option is AA→P,Q,S;B→T;C→Q,R;D→R (P) Siderite−FeCO3 (Q) Malachite−CuCO3.Cu(OH)2 (R) Bauxite−AlOx(OH)3−2x (S) Calamine−ZnCO3 (T) Argentite−Ag2S