Match the approximate pH values given in column I with appropriate solutions given in column II.
Column I Column II
A. 6.98 (p) 1M $N a O H$
B. 7.4 (q) 1M $H C l$
C. Zero (r) $1 \times 10^{- 8} H C l$
D. 14 (s) Blood

A-(s), B-(r), C-(p), D-(q)

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A-(r), B-(s), C-(q), D-(p)

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A-(q), B-(s), C-(r), D-(p)

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A-(p), B-(q), C-(s), D-(r)

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Solution

The correct option is B A-(r), B-(s), C-(q), D-(p)
A. $p H = - l o g (H)$ ion to the base 10.
B. Blood has $p H = 7.4$ slightly alkaline.
C. $p H$ of $1 M$ $H C l$ is $p H = - l o g (H)$ ion conc. $= - l o g (1) = 0$ $D .$ pOH=14-(\ log\ pH)=14-0=14$

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Column I	Column II
A. 6.98	(p) 1M $N a O H$
B. 7.4	(q) 1M $H C l$
C. Zero	(r) $1 \times 10^{- 8} H C l$
D. 14	(s) Blood

Match the approximate pH values given in column I with appropriate solutions given in column II.Column IColumn IIA. 6.98(p) 1M NaOHB. 7.4(q) 1M HClC. Zero(r) 1×10−8HClD. 14(s) Blood

The correct option is B A-(r), B-(s), C-(q), D-(p)A. pH=−log(H) ion to the base 10.B. Blood has pH=7.4 slightly alkaline.C. pH of 1M HCl is pH=−log(H) ion conc. =−log(1)=0D.pOH=14-(\ log\ pH)=14-0=14$

Match the approximate pH values given in column I with appropriate solutions given in column II.
Column I Column II
A. 6.98 (p) 1M $N a O H$
B. 7.4 (q) 1M $H C l$
C. Zero (r) $1 \times 10^{- 8} H C l$
D. 14 (s) Blood

The correct option is B A-(r), B-(s), C-(q), D-(p)
A. $p H = - l o g (H)$ ion to the base 10.
B. Blood has $p H = 7.4$ slightly alkaline.
C. $p H$ of $1 M$ $H C l$ is $p H = - l o g (H)$ ion conc. $= - l o g (1) = 0$ $D .$ pOH=14-(\ log\ pH)=14-0=14$