Question

Match the areas of the given parallelograms to their cost of tiling at the rate of ₹4 per sq.m.

• A. ₹440
• B. ₹160
• C. ₹50
• D. ₹56

Answer 1

Area of a parallelogram = base x height
Given, the cost of tiling at ₹4 per sq.m.
$\therefore$ Cost of tiling of each parallelogram = $4\times \text{Area of the parallelogram}$

Case 1 : b = 4 m, h =10 m
A= b x h = 4 x 10 = 40 sq.m
Cost of tiling = $4\times 40$ = ₹160

Case 2 : b = 2.5 m, h =5 m
A= b x h = 2.5 x 5 = 12.5 sq.m
Cost of tiling = $4\times 12.5$ = ₹50

Case 3 : b = 11 m, h =10 m
A= b x h = 11 x 10 = 110 sq.m
Cost of tiling = $4\times 110$ = ₹440

Case 4 : b = 3.5 m, h = 4 m
A= b x h =3.5 x 4 = 14 sq.m
Cost of tiling = $4\times 14$ = ₹56