Question

Match the column:
$\begin{array}{cccc}& & & \\ & Column-I& & Column-II\\ \left(a\right)& Ni& \left(p\right)& Elementshavingsamenumberofunpairedelectron\\ & & & intheirdipositiveincolumn-I\\ \left(b\right)& K& \left(q\right)& Atleast13electronsarehaving\\ & & & magneticquantumnumber{}^{\prime }zer{o}^{\prime }.\\ \left(c\right)& Mn& \left(r\right)& Atomisparamagnetic\\ \left(d\right)& Pd& \left(s\right)& Elementisnottransitionelemeent\\ & & \left(t\right)& Elementhavingpseudoinertgas\\ & & & configurationinitsdipositivecation\end{array}$

• A. (a) p, q, s; (b) r, s; (c) q, r; (d) p, q
• B. (a) p, q; (b) r, s; (c) q, r; (d) p, q,s
• C. (a) p, q, s; (b) q, r; (c) q, r, s; (d) p, q
• D. (a) p, q, s; (b) r, s; (c) p, q; (d) q, r

Answer 1

The correct option is A (a) p, q, s; (b) r, s; (c) q, r; (d) p, q

$N{i}_{\left(28\right)}-1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}3d^{8}4s^2$

$N{i}^{2+}-3d^{8}4s^0$

Number of unpaired electron in $N{i}^{2+}=2$
m - 0 present in all orbitals
2 + 2 + 2 + 2 + 2 + 2 + 1 = 13 (min)
Atom is paramagnetic.
It is transition element.
(b)
$K_{\left(19\right)}-1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^1$

$K^{2+}-3p^5$

m = 0
Number of unpaired electron in $K^{2+}=1$
m = 0 present in all orbitals
2 + 2 + 2 + 2 + 2 + 1 = 11 (min)
Atom is paramagnetic
It is not transition element
(c)
$M{n}_{\left(25\right)}-1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{5}M{n}^{2+}3d^5$
m = 2 + 2 + 2 + 2 + 2 + 2 + 1 = 13
(Transition element)
Number of unpaired electron in $M{n}^{2+}$ = 5
m = 0 present in all orbitals
2 + 2 + 2 + 2 + 2 + 2 + 1 = 13 (min)
Atom is paramagnetic.
It is transition element.
(d)
$Pd-1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{10}P{d}^{2+}4d^{6}5s^{2}4d^8$
Number of unpaired electron in $P{d}^{2+}$ = 2
m = 0 present in all orbitals
m = 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 1 = 19
Atom is diamagnetic.
It is transition element.