Match the column (for electrolytic refining of Cu):
$\begin{matrix} C o l u m n - I & C o l u m n - I I (a) & A n o d e & (p) & T h i n s h e e t s o f p u r e C u (b) & C a t h o d e & (q) & A n a q u e o u s s o l u t i o n o f c o p p e r s u l p h a t e c o n t a i n i n g H_{2} S O_{4} (c) & E l e c t r o l y t e & (r) & A g, A u (d) & A n o d e m u d & (s) & I m p u r e m e t a l o f C u \end{matrix}$

(a) s; (b) p; (c) q; (d) r

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(a) p; (b) s; (c) q; (d) r

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(a) r; (b) p; (c) q; (d) s

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(a) s; (b) r; (c) q; (d) p

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Solution

The correct option is A
(a) s; (b) p; (c) q; (d) r

Irrespective of the cell type - Daniel or electrolytic - at the anode, it is always oxidation.

Since the context is the electrolytic refining of copper, we want impure copper to become $C u^{2 +}$ ions and move into the electrolyte. We then expect $C u^{2 +}$ to get reduced at the cathode. So at the cathode, pure copper will be deposited (reduced). This clearly means that the anode will be made of impure metal, which has some valuable impurities like $A g, A u a n d P t$ . These impurities (metals which are highly unreactive and low on the electrochemical series), will get deposited below anode as anode mud.

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Similar questions

Match the column (for electrolytic refining of Cu):
$\begin{matrix} C o l u m n - I & C o l u m n - I I (a) & A n o d e & (p) & T h i n s h e e t s o f p u r e C u (b) & C a t h o d e & (q) & A n a q u e o u s s o l u t i o n o f c o p p e r s u l p h a t e c o n t a i n i n g H_{2} S O_{4} (c) & E l e c t r o l y t e & (r) & A g, A u (d) & A n o d e m u d & (s) & I m p u r e m e t a l o f C u \end{matrix}$

Q. Match the following by appropriately matching the lists based on the information given in

Column I

and

Column II

\begin{matrix} C o l u m n I & C o l u m n I I (T y p e o f △ A B C) a. cot \frac{A}{2} = \frac{b + c}{a} & p. always right angled b. a tan A + b tan B = (a + b) tan \frac{A + B}{2} & q. always isosceles c. a cos A = b cos B & r. may be right angled d. cos A = \frac{sin B}{2 sin C} & s. may be right angled isosceles \end{matrix}

Q. Match the Column-I with Column-II. Choose the correct option among the following
Column – I Column – II
(A) Borax (p)

s p^{3}

hybridization of B
(B)

B F_{3}

(q)

s p^{2}

hybridization of B
(C) Diborane (r) Triangular unit
(D) Boric acid (s) Tetrahedral unit

Match the type of fibre in column-I with their uses and characterstics in column-II
$\begin{matrix} Column - I & Column - II A. Acrylic & P. Contains repeating ester units B. Cellulose & Q. Used for making sweaters C. Polythene & R. Made up of large number of glucose units D. Terylene & S. Used for manufacturing toys. \end{matrix}$

$C o l u m n - I C o l u m n - I I A) Free radical substitution P) C H_{3} C H_{2} = C H_{2} + H B r O r g a n i c p e r o x i d e - --------- \to C H_{2} C H_{2} C H_{2} B r B) Electrophillic addition Q) C_{2} H_{5} O H H^{+} - - \to C_{2} H_{4} + H_{2} O C) Free radical addition R) Halogenation of alkanes D) Elimination S) C H_{3} C H = C H_{2} + H C l \to C H_{3} - C H - C H_{3} | C l$

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Match the column (for electrolytic refining of Cu): Column−I Column−II(a)Anode(p)Thin sheets of pure Cu(b)Cathode(q)An aqueous solution of copper sulphate containing H2SO4(c)Electrolyte(r)Ag,Au(d)Anode mud(s)Impure metal of Cu