Match the Column-I(Compound) with Column-II(Oxidation state of sulphur).
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Solution
A. Let the oxidation state of sulphur be x. Oxidation state of H and O are +1 and -2 respectively.
Therefore, 2×(+1)+x+3×(−2)=0⟹+2+x−6=0⟹x=+4
Hence, A matches with 4
B. Let the oxidation state of sulphur be x. Oxidation state of H and O are +1 and -2 respectively. There are 2 peroxy oxygen in this compound and hence, oxidation state for peroxy oxygen will be -1