Question

Match the Column-I(Compound) with Column-II(Oxidation state of sulphur).

Answer 1

A. Let the oxidation state of sulphur be x. Oxidation state of H and O are +1 and -2 respectively.

Therefore, $2\times (+1)+x+3\times (-2)=0⟹+2+x-6=0⟹x=+4$

Hence, A matches with 4

B. Let the oxidation state of sulphur be x. Oxidation state of H and O are +1 and -2 respectively. There are 2 peroxy oxygen in this compound and hence, oxidation state for peroxy oxygen will be -1

Therefore, $2\times (+1)+x+3\times (-2)+2\times (-1)=0⟹+2+x-6-2=0⟹x=+6$

Hence, B matches with 3

C. Let the oxidation state of sulphur be x. Oxidation state of H and O are +1 and -2 respectively.

Therefore, $2\times (+1)+2\times \left(x\right)+6\times (-2)=0⟹+2+2x-12=0⟹x=+5$

Hence, C matches with 1

D. Let the oxidation state of sulphur be x. Oxidation state of H and O are +1 and -2 respectively.

Therefore, $2\times (+1)+2\times \left(x\right)+4\times (-2)=0⟹+2+2x-8=0⟹x=+3$

Hence, D matches with 2