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Question

Match the Column I(Salt) with Column II(Degree of hydrolysis)

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Solution

A) NH4Cl(s)+H2O(l)NH4OH(aq)+Cl(aq)
We may write :
NH+4+H2OBOH+H+
C(1h) Ch Ch
Kh=Ch.ChC(1h)=C2h2C(1h)h2C
h=KhC
now, Kh=CBOH.COH.CH+CB+.COH=KwKb
h=KwKb.C
So, A2,3.
B) NaCl formed from strong acid HCl and strong base NaOH. No hydrolysis will take place.
B1.
C) CH3COONa
CH3COONa+H2OCH3COOH(aq)+Na+(aq)+OH(aq)
We may write : CH3COO+H2OCH3COOH+OH
C(1h) Ch Ch
Kh=Ch.ChC(1h)h2C
h=KhC C2
D) CH3COONH4
CH3COO+NH+4+H2OCH3COOH+NH4OH
C(1h) C(1h) Ch Ch
Kh=Ch.ChC(1h).C(1h)=(h1h)2h2 [Since 1h1]
h=Kh
So, D4

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