Match the column I with column II
A-P B-R C-P D-R
C1=C,C2=2C,C3=3C,C4=4C
Let q be the charge on C1. So charge on C2=q.
Let q3 be charge on C3 and q4 on C4.
So, q=q3+q4
And the potential drop across C3 and C4 is the same.
So, q33C=q44C
Solving we get, q3=3q7
and q4=4q7
Now by calculating potential drop as q/C and potential energy as q2/2C (for charge q and capacitance C),
We find that maximum potential difference is across C1, minimum across C3 and C4. And potential energy is maximum for C1 and minimum for C3.