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Question

Match the column I with column II


A

A-P B-R C-P D-R

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B

A-P B-Q C-P,S D-R

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C

A-Q B-Q C-S D-Q

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D

A-Q B-Q C-Q,R D-P

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Solution

The correct option is A

A-P B-R C-P D-R


C1=C,C2=2C,C3=3C,C4=4C

Let q be the charge on C1. So charge on C2=q.

Let q3 be charge on C3 and q4 on C4.

So, q=q3+q4

And the potential drop across C3 and C4 is the same.

So, q33C=q44C

Solving we get, q3=3q7

and q4=4q7

Now by calculating potential drop as q/C and potential energy as q2/2C (for charge q and capacitance C),

We find that maximum potential difference is across C1, minimum across C3 and C4. And potential energy is maximum for C1 and minimum for C3.


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