Match the column I with column II and mark the appropriate choice- Column IColumn II A CH3NH2 - CHCl3-KOH i CH3NH2 B CH3CONH2-Br2- KOH - ii CH3OH C CH3NH2 - NaNO2 - HCl - iii CH3NHCH3 D CH3NC - 4H iv CH3NC

The correct option is B (A) → (iv) , (B) → (i) , (C) → (ii) , (D) → (iii) #160;Carbylamine reaction:(A) CH_3NH_2 + CHCl_3 +KOH CH_3NC Hof ...

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Byju's Answer

Standard XII

Chemistry

Preparation of Haloalkanes from Alcohol

Match the col...

Question

Match the column I with column II and mark the appropriate choice.
Column I Column II
$(A)$ $C H_{3} N H_{2} + C H C l_{3} + K O H Δ - \to$ $(i)$ $C H_{3} N H_{2}$
$(B)$ $C H_{3} C O N H_{2} + B r_{2} + K O H \to$ $(i i)$ $C H_{3} O H$
$(C)$ $C H_{3} N H_{2} + N a N O_{2} + H C l \to$ $(i i i)$ $C H_{3} N H C H_{3}$
$(D)$ $C H_{3} N C + 4 H P t - \to$ $(i v)$ $C H_{3} N C$

(A) \to (i), (B) \to (i i), (C) \to (i i i), (D) \to (i v)

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(A) \to (i i), (B) \to (i i i), (C) \to (i v), (D) \to (i)

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(A) \to (i v), (B) \to (i), (C) \to (i i), (D) \to (i i i)

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(A) \to (i i i), (B) \to (i v), (C) \to (i), (D) \to (i i)

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Solution

The correct option is B $(A) \to (i v), (B) \to (i), (C) \to (i i), (D) \to (i i i)$
Carbylamine reaction:
(A) $C H_{3} N H_{2} + C H C l_{3} + K O H Δ - \to C H_{3} N C$

Hoffman Bromamide reaction:
(B) $C H_{3} C O N H_{2} + B r_{2} + K O H \to C H_{3} N H_{2}$

Reaction with $H N O_{2}$
(c) $C H_{3} N H_{2} + N a N O_{2} + H C l \to C H_{3} O H$

Reduction with $H_{2} / P t$ :
(D) $C H_{3} N C + 4 H P t / P d - --- \to C H_{3} N H C H_{3}$

Option C is correct.

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	Column I		Column II
$(A)$	$C H_{3} N H_{2} + C H C l_{3} + K O H Δ - \to$	$(i)$	$C H_{3} N H_{2}$
$(B)$	$C H_{3} C O N H_{2} + B r_{2} + K O H \to$	$(i i)$	$C H_{3} O H$
$(C)$	$C H_{3} N H_{2} + N a N O_{2} + H C l \to$	$(i i i)$	$C H_{3} N H C H_{3}$
$(D)$	$C H_{3} N C + 4 H P t - \to$	$(i v)$	$C H_{3} N C$

Match the column I with column II and mark the appropriate choice. Column IColumn II(A)CH3NH2+CHCl3+KOHΔ−→(i)CH3NH2(B)CH3CONH2+Br2+KOH→(ii)CH3OH(C)CH3NH2+NaNO2+HCl→(iii)CH3NHCH3(D)CH3NC+4HPt−→(iv)CH3NC