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Question

Match the column I with column II and mark the appropriate choice.

Column IColumn II
(A)Hydrolysis of benzene diazonium chloride(i)p- Cresol
(B)Phenol + methyl chloride in presence of an, AlCl3
(ii)Salicylic acid
(C)Reaction of sodium phenoxide with CO2(iii)Picric acid
(D)Phenol + Conc. HNO3(iv)Phenol

A
(A) (i), (B) (iii), (C)(ii), (D) (iv)
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B
(A) (ii), (B) (iii), (C) (iv), (D) (i)
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C
(A) (iv), (B) (i), (C) (ii), (D) (iii)
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D
(A) (iii), (B) (iv), (C) (i), (D) (ii)
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Solution

The correct option is A (A) (iv), (B) (i), (C) (ii), (D) (iii)
A. Hydrolysis of benzene diazonium chloride gives phenol as:
C6H5N2ClH+/H2OC6H5OH+N2+HCl
B. Phenol + methyl chloride in presence of anhy. AlCl3 undergoes Friedel craft alkylation at ortho and para position. The major product is p-methyl phenol or p-cresol as:
C6H5OH+CH3ClAlCl3p(CH3)C6H4OH
C. Reaction of sodium phenoxide with CO2 is a Kolbe's reaction and gives COOH at ortho to OH on benzene ring. The product is called salicylic acid as:
C6H5ONa+CO2o(COOH)C6H4OH
D. Phenol + Conc. HNO3 gives trinitro product called picric acid as:
C6H5OH+conc.HNO3o,o,p(NO2)3C6H2OH
Thus (A) - (iv), (B) - (i), (C)- (ii), (D)- (iii)

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