Question

Match the column I with column II and mark the appropriate choice

	Column I		Column II
(A)	Quick lime	(i)	$Ca{H}_2$
(B)	Slaked lime	(ii)	$Ba(OH{)}_2$
(C)	Baryta water	(iii)	$Ca(OH{)}_2$
(D)	Hydrolith	(iv)	$CaO$

• A. $\left(A\right)\to \left(i\right),\left(B\right)\to \left(ii\right),\left(C\right)\to \left(iii\right),\left(D\right)\to \left(iv\right)$
• B. $\left(A\right)\to \left(iii\right),\left(B\right)\to \left(ii\right),\left(C\right)\to \left(i\right),\left(D\right)\to \left(iv\right)$
• C. $\left(A\right)\to \left(i\right),\left(B\right)\to \left(iii\right),\left(C\right)\to \left(iv\right),\left(D\right)\to \left(ii\right)$
• D. $\left(A\right)\to \left(iv\right),\left(B\right)\to \left(iii\right),\left(C\right)\to \left(ii\right),\left(D\right)\to \left(i\right)$

Answer 1

Answer: (D)

$\left(A\right)\to \left(iv\right),\left(B\right)\to \left(iii\right),\left(C\right)\to \left(ii\right),\left(D\right)\to \left(i\right)$

1. Quick lime is Calcium oxide -$\left(CaO\right)$.It is a key ingredient for the process of making cement. As a cheap and widely available alkali.
   
2. Slaked lime which is Calcium hydroxide-$Ca(OH{)}_2$. Slaked lime is used for mortar, plaster, and cement in buildings and other structures.
3. Bartya water-$Ba(OH{)}_2$ Industrially, barium hydroxide is used as the precursor to other barium compounds. The monohydrate is used to dehydrate and remove sulfate from various products. This application exploits the very low solubility of barium sulfate. This industrial application is also applied to laboratory uses.

Calcium hydride ($Ca{H}_2$) is known as hydrolith. It is used as reducing agent . It is used as a reducing agent, it is mainly used as a source of Hydrogen gas.

Hence option D matches the correct answer to all the options.