Match the column I with column IIWhineColumn - I-Column IIWhlineB- In the case of - a pendulum- - work - done by - tension-Q- Net Work done is zerollhlineC- - When there is - friction-R- The only force acting is gravity WhlineD- In- Projectile - motion- S- - Work - done - by - force - a - roundtrip - is - not - equal - to zero- Whline array

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Byju's Answer

Standard XII

Physics

Angular Analogue of Linear Momentum

Match the col...

Question

Match the column I with column II
$\begin{matrix} C o l u m n I & C o l u m n I I A . W h e n n o n - c o n s e r v a t i v e f o r c e s a r e a c t i n g & P . W o r k d o n e b y f o r c e m a y b e n e g a t i v e . B . I n t h e c a s e o f a p e n d u l u m, w o r k d o n e b y t e n s i o n & Q . N e t W o r k d o n e i s z e r o C . W h e n t h e r e i s f r i c t i o n & R . T h e o n l y f o r c e a c t i n g i s g r a v i t y D . I n P r o j e c t i l e m o t i o n & S . W o r k d o n e b y f o r c e i n a r o u n d t r i p i s n o t e q u a l t o z e r o . \end{matrix}$

A-Q,R B-Q,R C-Q,R D-P,R

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A-P,S B-Q C-P,S D-R

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A-Q B-Q,R C-S D-Q

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A-Q B-Q C-Q,R D-P

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Solution

The correct option is B A-P,S B-Q C-P,S D-R
A. When non – conservative forces are acting work done in a round trip is not equal to zero.

B. In case of a pendulum, the sum of kinetic energy and potential energy is constant.

C. When there is friction, work done is negative. In projectile motion, the only force acting is gravity.

D. In uniform circular motion, there is no work done by a body.

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Similar questions

Match the column I with column II :
$\begin{matrix} c o l u m n 1 & c o l u m n 2 a) W h e n n o n c o n s e r v a t i v e f o r c e s a r e a c t i n g & p) w o r k d o n e b y f o r c e m a y b e n e g a t i v e b) I n t h e c a s e o f a p e n d u l u m, w o r k d o n e b y t h e t e n s i o n & q) N e t w o r k d o n e i s z e r o c) W h e n t h e r e i s f r i c t i o n & r) T h e o n l y f o r c e a c t i n g i s g r a v i t y d) I n P r o j e c t i l e m o t i o n & s) W o r k d o n e b y f o r c e i n a r o u n d t r i p i s n o t e q u a l t o z e r o \end{matrix}$

Q. Match the Column I with Column II.

	Column I		Column II
(A)	When a body does work against friction, its kinetic energy	(p)	independent of time
(B)	Work done by a body is	(q)	time
(C)	Power of a body varies inversely as	(r)	force must be conservative
(D)	When work done over a closed path is zero	(s)	decreases

Q. In Column I some statements are given related to work done by a force on an object while in Column II the sign and information about value of work done is given. Match the entries in Column I with the entries in Column II.

Q. A block of mass

m

is stationary with respect to a rough wedge as shown in figure. Starting from rest in time

t

.
(Given that

m = 1 kg, θ = 30^{\circ}, a = 2 {m/s}^{2}, t = 4 s

)
Match Column

I

with column

I I

\begin{matrix} Column-I & Column-II (a) Work done on block by gravity & (p) 144 J (b) Work done on block by normal reaction & (q) 32 J (c) Work done on block by friction & (r) 56 J (d) Work done on block by all the forces & (s) 48 J (t) None \end{matrix}

Q. When work done by force of gravity is negative (Assume only gravitational force to be acting).

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