Question

Match the Column-I with Column-II. Choose the correct option among the following
Column – I Column – II
(A) Borax (p) $s{p}^3$ hybridization of B
(B) $B{F}_3$ (q) $s{p}^2$ hybridization of B
(C) Diborane (r) Triangular unit
(D) Boric acid (s) Tetrahedral unit

• A. A-(p, q, r, s), B-(q, r), C-(p, s), D-(q, r)
  
• B. A-(r, s), B-(p, q), C-(p, q, r, s), D-(s)
  )
• C. A-(p, q,), B-(q, r), C-(p, s), D-(q, r)
  
• D. (r, s), B-(p, q), C-(s), D-(p, r)

Answer 1

The correct option is C A-(p, q,), B-(q, r), C-(p, s), D-(q, r)


In borax two boron atoms are $s{p}^2$ hybridised triangular geometry while other two are $s{p}^3$ hybridised tetrahedral unit.
$B{F}_3$ has $s{p}^2$ hybridised, triangular structure.
Diborane has $s{p}^3$ hybridised, tetrahedral structure.
Boric acid has $s{p}^2$ hybridised, triangular structure.