Match the column - I with column - II, for an ideal gas going through following processes.
A
A→r,B→q,C→p
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B
A→q,B→q,C→p
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C
A→p,B→q,C→r
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D
A→r,B→p,C→q
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Solution
The correct option is CA→p,B→q,C→r For graph (A)
tanθ = constant ⇒ Slope (m) = constant Here, m=TP ⇒TP = constant or PT = constant It represents constant volume process, hence it is isometric process. For graph (B) S= Constant ⇒ΔS=ΔQT For S= constant, ΔS=0 ⇒ΔQ=0 Hence it reprents adiabatic process For graph (C), T= Constant for all values of pressure Hence, it represents isothermal process.