Match the column I with column IIIn the circuit shown in fig- C 1- C - C 2-2 C - C 3-3 C and C 4-4 CWlineColumn - I- Column - II MhlineC Maximum energy -R across C3Wllhlinelendarray - A- A-Q B-Q C-S D-Q - B- A-Q B-Q C-Q-R D-P - C- A-P B-R -S C-P D-R -D- A-P - B-Q C-P-S D-R -

The correct option is C A P B R ,S C P D Rq_c_1=q amp; say then amp; V_c_1=q/c q_c_2=q amp; amp;V_c_2=q/2c q_c_3=3/ ...

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Byju's Answer

Standard XII

Physics

Resistors in Series and Parallel

Match the col...

Question

Match the column I with column II
In the circuit shown in fig. $C_{1} = C, C_{2} = 2 C, C_{3} = 3 C a n d C_{4} = 4 C$

$\begin{matrix} C o l u m n - I & C o l u m n - I I (A) M a x i m u m p o t e n t i a l d i f f e r e n c e & (P) a c r o s s C_{1} (B) M i n i m u m p o t e n t i a l d i f f e r e n c e & (Q) a c r o s s C_{2} (C) M a x i m u m p o t e n t i a l e n e r g y & (R) a c r o s s C_{3} (D) M i n i m u m p o t e n t i a l e n e r g y & (S) a c r o s s C_{4} \end{matrix}$

A-P B-R ,S C-P D-R

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A-P B-Q C-P,S D-R

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A-Q B-Q C-S D-Q

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A-Q B-Q C-Q,R D-P

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Solution

The correct option is A A-P B-R ,S C-P D-R
$\begin{matrix} q_{c_{1}} = q & s a y t h e n & V_{c_{1}} = \frac{q}{c} q_{c_{2}} = q & V_{c_{2}} = \frac{q}{2 c} q_{c_{3}} = \frac{3}{7} q & V_{c_{4}} = \frac{3 q}{7 (3) c} q_{c_{4}} = \frac{4}{7} q & V_{c_{4}} = \frac{4 q}{7 (4) c} V_{c_{1}} = \frac{q^{2}}{2 c} & V_{c_{2}} = \frac{q^{2}}{4 c} V_{c_{3}} = \frac{3 q^{2}}{98 c} & V_{c_{4}} = \frac{4 q^{2}}{98 c} \end{matrix}$

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$C o l u m n - I C o l u m n - I I A) Free radical substitution P) C H_{3} C H_{2} = C H_{2} + H B r O r g a n i c p e r o x i d e - --------- \to C H_{2} C H_{2} C H_{2} B r B) Electrophillic addition Q) C_{2} H_{5} O H H^{+} - - \to C_{2} H_{4} + H_{2} O C) Free radical addition R) Halogenation of alkanes D) Elimination S) C H_{3} C H = C H_{2} + H C l \to C H_{3} - C H - C H_{3} | C l$

Match Column I with Column II with reference to types of reaction:

$\begin{matrix} Column I & Column II A. & Ionization reaction & p. & {CH}_{4} + 2 O_{2} \to {CO}_{2} + 2 H_{2} O B. & Dissociation reaction & q. & H_{2} O_{2} \to H_{2} O + O_{2} C. & Decomposition reaction & r. & Mg {Cl}_{2} \to {Mg}^{2 +} + 2 {Cl}^{-} D. & Combustion reaction & s. & {H_{2} O}_{(basic)} + {H_{2} O}_{(acidic)} \to H_{3} O^{+} + {OH}^{-} \end{matrix}$

Match the column I with column II :
$\begin{matrix} c o l u m n 1 & c o l u m n 2 a) W h e n n o n c o n s e r v a t i v e f o r c e s a r e a c t i n g & p) w o r k d o n e b y f o r c e m a y b e n e g a t i v e b) I n t h e c a s e o f a p e n d u l u m, w o r k d o n e b y t h e t e n s i o n & q) N e t w o r k d o n e i s z e r o c) W h e n t h e r e i s f r i c t i o n & r) T h e o n l y f o r c e a c t i n g i s g r a v i t y d) I n P r o j e c t i l e m o t i o n & s) W o r k d o n e b y f o r c e i n a r o u n d t r i p i s n o t e q u a l t o z e r o \end{matrix}$

Q. Three rods of material x and two rods of material y are connected as shown in figure. All the rods are of identical length and cross – sectional area. The end A is maintained at

100^{\circ} C

and the junction D at

0^{\circ} C

. It is given that resistance of rod of material x is R. Further,

K_{x} = 2 K_{y}

Match the entries of column I and column II

\begin{matrix} C o l u m n - I & C o l u m n I I A . T e m p e r a t u r e o f j u n c t i o n B & P . D o e s n o t b e h a v e l i k e a b a l a n c e d w h e a t s t o n e^{'} s b r i d g e B . T e m p e r a t u r e o f j u n c t i o n C & Q . I s t w i c e o f t h e o t h e r . C . T h i s n e t w o r k i s & R . \frac{400}{7} d e g r e e c e l s i u s D . R e s i s t a n c e o f r o d o f m a t e r i a l y & S . \frac{300}{7} d e g r e e c e l s i u s \end{matrix}

Let B and C be points (12, 19) and (23, 20) respectively. Let A $(α, β)$ be a point such that area of triangle formed by the points A, B and C is 70. Also the slope of the median through A is – 5.

Match the following:

\begin{matrix} C o l u m n I & C o l u m n I I (a) & A p o s s i b l e v a l u e α + β i s & (p) & 2 (b) & A p o s s i b l e v a l u e β - 2 α i s & (q) & 27 (c) & A p o s s i b l e v a l u e 3 α - β - 11 i s & (r) & - 33 (d) & A p o s s i b l e v a l u e α - 2 β + 16 i s & (s) & 47 (t) & 28 \end{matrix}

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Match the column I with column II In the circuit shown in fig. C1=C,C2=2C,C3=3C and C4=4C Column−IColumn−II(A) Maximum potential difference(P) across C1(B) Minimum potential difference(Q) across C2(C) Maximum potential energy(R) across C3(D) Minimum potential energy(S) across C4

The correct option is A A-P B-R ,S C-P D-Rqc1=qsay thenVc1=qcqc2=q Vc2=q2cqc3=37q Vc4=3q7(3)cqc4=47q Vc4=4q7(4)cVc1=q22c Vc2=q24cVc3=3q298c Vc4=4q298c