Question

Match the columns.

Column-I	Column-II
(i) When an odd Integer 'a' is divided by $2$, then remainder r can be	(p) $5$
(ii) When an integer 'a' whose unit digit is $4$ is divided by $5$, then remainder r can be	(q) $1$
(iii) A whole number lying between $\sqrt{2}$ and $2\sqrt{2}$ is	(r) $2$
(iv) If the digit at the units place of a number is $5$, then it is surely divisible by	(s) $4$

• A. (i) $\to$ (p), (ii) $\to$ (r), (iii) $\to$ (s), (iv) $\to$ (q)
• B. (i) $\to$ (q), (ii) $\to$ (s), (iii) $\to$ (p), (iv) $\to$ (r)
• C. (i) $\to$ (p), (ii) $\to$ (r), (iii) $\to$ (q), (iv) $\to$ (s)
• D. (i) $\to$ (q), (ii) $\to$ (s), (iii) $\to$ (r), (iv) $\to$ (p)

Answer 1

The correct option is D (i) $\to$ (q), (ii) $\to$ (s), (iii) $\to$ (r), (iv) $\to$ (p)

For the $i$ odd numbers are represented by $2K+1$ where $K$ is an integer when its divided by $2$ then remainder is always $1$

For $ii$ as per divisibility rule when an integer whose unit digit is 4 is divided by 5 so remainder will be $4$ .

For $iii$ $\sqrt{2}=1.414$ and $2\sqrt{2}=2.828$ whole number lying between them is $2$.

For $iv$ again as per divisibility rule if the last digit is a $5$ or $0$ then number is divisible by $5$ .

Hence option D is correct.