Question

Match the columns I and II, and choose the correct combination from the options given. Column I Column II

a.	Bacteriophage Lambda	i.	$5386$nucleotides
b.	Bacteriophage $ɸ\times 174$	ii.	$48502bp$
c.	$Escherichiacoli$	iii.	$4.6\times {10}^{6}bp$
d.	$Homosapiens$	iv.	$6.6\times {10}^{9}bp$

• A. a b c d
  i ii iv iii
  
• B. a b c d
  ii i iii iv
  
• C. a b c d
  i ii iii iv
  
• D. a b c d
  ii i iv iii

Answer 1

The correct option is B a b c d

ii i iii iv

Introduction
The given table shows the size of DNA molecules in different organisms. DNA is a double stranded helical molecule in which each strand is composed of repeating units of deoxyribonucleotides. The length of the DNA molecule is defined in terms of the number of nucleotides or nucleotide/base pairs (bp) present in it.
Bacteriophage Lambda - 48502 bp
The genome of bacteriophage lambda is composed of DNA that is 48502 base pairs (bp) long.
Bacteriophage ɸ × 174 - 5386 nucleotides
The genome of bacteriophage ɸ × 174 consists of DNA that is 45386 nucleotides long.
Escherichia coli - 4.6 × 106 bp
The genomic DNA in Escherichia coli is 4.6 × 106 bp long.
Homo sapiens - 6.6 × 109 bp
Humans or Homo sapiens are complex eukaryotic organisms with very long DNA molecules in their genome. A diploid set of human DNA is composed of 6.6 × 109 base pairs (bp).
Final answer
(B) a b c d
ii i iii iv