Question

Match the columns with correct combination of endosperm chromosomes.

	Column I		Column II
(a)	Pisum sativum	(i)	$72$
(b)	Oryza sativa	(ii)	$24$
(c)	Nicotiaba tabacum	(iii)	$60$
(d)	Allium cepa	(iv)	$36$
			$21$

• A. a-iv, b-i, c-ii, d-v
• B. a-i, b-ii, c-v, d-iv
• C. a-ii, b-v, c-iii, d-i
• D. a-v, b-iv, c-i, d-ii

Answer 1

The correct option is D a-v, b-iv, c-i, d-ii

During triple fusion the second sperm nucleus(n) fuses with the polar nuclei(2n) and forms the endosperm(3n).

• Pisum sativum (pea) is diploid (2n) having 14 chromosomes. Therefore n=7 and 3n=21.
• Oryza sativa (rice) is 2n=24. So, n=12 and 3n=36
• Nicotiaba tabacum (tobacco) is 2n=48. So n=24 and 3n=72.
• Allium cepa (onion) is 2n=16. So n=8 and 3n=24

So, the correct option is D.