Question

Match the complex ions in column-I with their information in column-II
$\begin{array}{cccc}& \text{Columns - I}& & \text{Column - II}\\ \left(P\right)& [MnC{l}_6{]}^{2-}& \left(2\right)& s{p}^3{d}^2\text{hybridisation}\\ \left(Q\right)& \left[Fe\right(CN{)}_6{]}^{3-}& \left(2\right)& \text{Is attracted toward a magnet}\\ \left(R\right)& [Co{F}_6{]}^{3-}& \left(3\right)& \text{Is low spin complex}\\ \left(S\right)& \left[Fe\right(N{H}_3{)}_6{]}^{2+}& \left(4\right)& \text{Oxidation state of metal}\ge +3\\ & & \left(5\right)& \text{Is inner orbital octa hedral complex}\end{array}$
Match each product in LIST-I with one or more reaction in LIST-II and choose the correct option.

• A. $P\to 3.4;Q\to 1,2;R\to 1,2,4;S\to 3,5$
• B. $P\to 3.5;Q\to 1,2,5;R\to 1,2,3;S\to 4,5$
• C. $P\to 2,3.4,5;Q\to 2,\mathrm{3.4.5};R\to 1,2,4;S\to 1,2$
• D. $P\to 1,23.5;Q\to 1,22,4;R\to 1,21;S\to 1,24$

Answer 1

The correct option is D $P\to 1,23.5;Q\to 1,22,4;R\to 1,21;S\to 1,24$

5.50

$AgBr\left(s\right)\rightleftharpoons \underset{s+{10}^{-7}}{A{g}^{+}}+\underset{s}{B{r}^{-}}$

$Ksp=12\times {10}^{-14}=(s+{10}^{-7})s$

$\Rightarrow s=3\times {10}^{-7}$

$k=\frac{6\times {10}^{-3}\times 4\times {10}^{-7}}{{10}^{-3}}+\frac{8\times {10}^{-3}\times 3\times {10}^{-7}}{{10}^{-3}}+\frac{7\times {10}^{-3}\times {10}^{-7}}{{10}^{-3}}=5.5\times {10}^{-6}$