Question

Match the complex ions listed in column-I with the characteristics listed in column-II using the codes given below.

Column-I	Column-II
(a) $\left[Ni\right(N{H}_3{)}_6{]}^{2+}$	(p) $d^{2}s{p}^3$ and diamagnetic
(b) $\left[Cr\right(N{H}_3{)}_6{]}^{3+}$	(q) $s{p}^3{d}^2$ and diamagnetic
(c) $\left[Co\right(N{H}_3{)}_6{]}^{3+}$	(r) $s{p}^3{d}^2$ and two unpaired electrons
(d) $\left[Zn\right(N{H}_3{)}_6{]}^{2+}$	(s) $d^{2}s{p}^3$ and three unpaired electrons.

• A. a-r, b-s, c-p, d-q
• B. a-s, b-r, c-q, d-p
• C. a-r, b-s, c-q, d-p
• D. a-p, b-q, c-r, d-s

Answer 1

The correct option is A a-r, b-s, c-p, d-q

The complex $\left[Ni\right(N{H}_3{)}_6{]}^{2+}$ undergoes $s{p}^3{d}^2$ hybridization. It contains two unpaired electrons and is paramagnetic.
The complex $Cr(N{H}_3{)}_6{]}^{3+}$ undergoes $d^{2}s{p}^3$ hybridization. It contains three unpaired electrons and is paramagnetic.
The complex $Co\left(N{H}_3{)}_6\right]3+$ undergoes $d^{2}s{p}^3$ hybridization. It contains no unpaired electrons and is diamagnetic.
The complex $\left[Zn\right(N{H}_3{)}_6{]}^{2+}$ undergoes $s{p}^3{d}^2$ hybridization. It contains no unpaired electrons and is diamagnetic.