Question

Match the compounds given in column I with column II and mark the appropriate choice.

	Column I		Column II
(A)	Benzenesulphonyl chloride	(i)	Zwitter ion
(B)	Sulphanilic acid	(ii)	Hinsberg reagent
(C)	Alkyldiazonium salts	(iii)	Dyes
(D)	Aryldiazonium salts	(iv)	Conversion to alcohols

• A. $\left(A\right)\to \left(iv\right)\left(B\right)\to \left(iii\right)\left(C\right)\to \left(i\right)\left(D\right)\to \left(ii\right)$
• B. $\left(A\right)\to \left(ii\right)\left(B\right)\to \left(iv\right)\left(C\right)\to \left(iii\right)\left(D\right)\to \left(i\right)$
• C. $\left(A\right)\to \left(ii\right)\left(B\right)\to \left(i\right)\left(C\right)\to \left(iv\right)\left(D\right)\to \left(iii\right)$
• D. $\left(A\right)\to \left(ii\right)\left(B\right)\to \left(iii\right)\left(C\right)\to \left(iv\right)\left(D\right)\to \left(i\right)$

Answer 1

The correct option is C $\left(A\right)\to \left(ii\right)\left(B\right)\to \left(i\right)\left(C\right)\to \left(iv\right)\left(D\right)\to \left(iii\right)$

(i) Benzene-sulphonyl chloride is the Hinsberg reagent

This is used to distinguish between $1^o,2^o$ and $3^o$ amine.

(ii) Sulphanilic acid rearranging to zwitterion

(ii) Alkyl diazonium salts lose nitrogen gas and then treated with water to convert to alcohol.

(iv) Aryl diazonium salts are coupled with aromatic amines/phenol to form dyes.

A) Benzenesulphorylchloride $⟶$ Hinsberg Reagent

B) Sulphanilic Acid $⟶$zwitterion

C) Alkyldiazonium salts $⟶$ Conversion to alcohols

D) Aryldiazonium Salts $⟶$ Dyes